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Harvard-MIT Mathematics Tournament

Algebra Difficulty 4.2 AIME Find the answer United States

Problem:

Let pp be the answer to this question. If a point is chosen uniformly at random from the square bounded by x=0x=0, x=1x=1, y=0y=0, and y=1y=1, what is the probability that at least one of its coordinates is greater than pp?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

The probability that a randomly chosen point has both coordinates less than pp is p2p^{2}, so the probability that at least one of its coordinates is greater than pp is 1−p21 - p^{2}. Since pp is the answer to this question, we have 1−p2=p1 - p^{2} = p, and the only solution of pp in the interval [0,1][0,1] is 5−12\frac{\sqrt{5} - 1}{2}.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.