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Number theory Difficulty 5.0 AIME Prove it Brazil

Determine if there exist positive integers n,a1,a2,,a2012n, a_1, a_2, \dots, a_{2012} all greater than 1, such that
n2=a12+a23+a35++aipi++a2012p2012, n^2 = a_1^2 + a_2^3 + a_3^5 + \dots + a_i^{p_i} + \dots + a_{2012}^{p_{2012}},
where pip_i is the i-th prime.

Solution

Just pick any odd a2a_2, any even a3,,a2012a_3, \dots, a_{2012}. Then a23++a2012p2012=2N+1a_2^3 + \dots + a_{2012}^{p_{2012}} = 2N+1 is odd. Then pick a1=Na_1 = N and n=N+1n = N+1, and n2a12=(N+1)2N2=2N+1n^2 - a_1^2 = (N+1)^2 - N^2 = 2N+1.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.