Maths Olympiad Prep

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Geometry Difficulty 4.9 AIME Prove it United States

Problem:

Let triangle ABCA B C have a right angle at CC, and let MM be the midpoint of the hypotenuse ABA B. Choose a point DD on line BCB C so that angle CDMC D M measures 3030 degrees. Prove that the segments ACA C and MDM D have equal lengths.

Solution

Solution:

Drop the perpendicular from MM to BCB C. Let PP be the point where this perpendicular meets the line BCB C. Since MPB\angle M P B and ACB\angle A C B are both right angles, and triangle MPBM P B and triangle ACBA C B share the angle at BB, triangle MPBM P B and triangle ACBA C B are similar. Since the length of MBM B is half the length of BAB A, side MPM P must be half the length of ACA C. But triangle MPDM P D is a 3030-6060-9090 triangle, so the length of MPM P is also half the length of MDM D. Therefore, the length of ACA C equals the length of MDM D.

Figure 1

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.