Let ABC be a triangle with ∠A<∠B≤∠C, M and N the midpoints of sides CA and AB, respectively, and P and Q the projections of B and C on the medians CN and BM, respectively. Prove that the quadrilateral MNPQ is cyclic.
Solution
Because ∠BPC=∠BQC=90∘, quadrilateral BCQP is cyclic and therefore ∠CPQ=∠CBQ. Because M and N are midpoints of sides AC and AB, segment MN is parallel to side BC. Hence ∠NMQ=∠CBQ.
We deduce that ∠NMQ=∠CPQ. This proves that quadrilateral MNPQ is cyclic.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: MathNet,
licensed CC-BY-4.0.
Statement and solution reproduced as published; topic and difficulty added by this site.