Maths Olympiad Prep

Library / /3 of 4

, 2003

Algebra Difficulty 4.8 AIME Prove it Italy

Problem:

For every integer nn, let S(n)S(n) be the sum of the digits of nn (in base ten). What is the smallest integer NN for which S(S(N))10S(S(N)) \geq 10?

Solution

Solution:

The answer is 199199. Indeed if nn had 11 or 22 digits, n99n \leq 99, and then S(n)18S(n) \leq 18 and S(S(n))9S(S(n)) \leq 9, so nn has at least three digits. Observe that for n198n \leq 198, still S(n)18S(n) \leq 18. Instead if n=199n=199, S(n)=19S(n)=19 and S(S(n))=10S(S(n))=10, as sought.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from it; metadata (topic, difficulty) added by this project.