Maths Olympiad Prep

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Geometry Difficulty 5.2 AIME, harder Prove it United States

Problem:

In circle ω\omega, two perpendicular chords intersect at a point PP. The two chords have midpoints M1M_{1} and M2M_{2} respectively, such that PM1=15P M_{1}=15 and PM2=20P M_{2}=20. Line M1M2M_{1} M_{2} intersects ω\omega at points AA and BB, with M1M_{1} between AA and M2M_{2}. Compute the largest possible value of BM2AM1B M_{2}-A M_{1}.

Solution

Solution:

Let OO be the center of ω\omega and let MM be the midpoint of ABA B (so MM is the foot of OO to M1M2M_{1} M_{2}). Since OM1PM2O M_{1} P M_{2} is a rectangle, we easily get that MM1=16M M_{1}=16 and MM2=9M M_{2}=9. Thus, BM2AM1=MM1MM2=7B M_{2}-A M_{1}=M M_{1}-M M_{2}=7.

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