Maths Olympiad Prep

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Combinatorics Difficulty 6.8 National olympiad Prove it Netherlands

Daan distributes the numbers 11 to 99 over the nine squares of a 3×33 \times 3 table (each square receives exactly one number). Then, in each row, Daan circles the median number (the number that is neither the smallest nor the largest of the three). For example, if the numbers 88, 11, and 22 are in one row, he circles the number 22. He does the same for each column and each of the two diagonals. If a number is already circled, he does not circle it again.

<table><tr><td>(⑧)</td><td>1</td><td>(②)</td></tr><tr><td>7</td><td>(⑥)</td><td>(③)</td></tr><tr><td>9</td><td>(⑤)</td><td>4</td></tr></table>

He calls the result of this process a *median table*. Above, you can see a median table that has 55 circled numbers.

a. What is the smallest possible number of circled numbers in a median table?
*Prove that a smaller number is not possible and give an example in which a minimum number of numbers is circled.*

b. What is the largest possible number of circled numbers in a median table?
*Prove that a larger number is not possible and give an example in which a maximum number of numbers is circled.*

Solution

a. The smallest possible number of circled numbers is 33. Fewer than 33 is not possible since in each row at least one number is circled (and these are three different numbers).

On the right, a median table is shown in which only 33 numbers are circled. In the rows, the numbers 77, 55, 33 are circled, in the columns the numbers 33, 55, 77, and on the diagonals the numbers 55 and 55. Together, these are three different numbers: 33, 55, and 77.

<table><tr><td>4</td><td>9</td><td>7</td></tr><tr><td>2</td><td>5</td><td>8</td></tr><tr><td>3</td><td>1</td><td>6</td></tr></table>

b. The largest possible number of circled numbers is 77. More than 77 is not possible, since the numbers 99 and 11 are never circled, hence no more than 92=79 - 2 = 7 numbers are circled.

On the right, a median table is shown in which 77 numbers are circled. In the rows, the numbers 22, 66, 88 are circled, in the columns the numbers 77, 55, 33, and on the diagonals the numbers 44 and 55. Together, these are the numbers 22, 33, 44, 55, 66, 77, 88.

<table><tr><td>4</td><td>1</td><td>2</td></tr><tr><td>7</td><td>5</td><td>6</td></tr><tr><td>8</td><td>9</td><td>3</td></tr></table>

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Source: MathNet, licensed CC-BY-4.0. Statement and solution reproduced as published; topic and difficulty added by this site.