Maths Olympiad Prep

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Geometry Difficulty 4.7 AIME Prove it United States

Problem:

A point on a circle inscribed in a square is 11 and 22 units from the two closest sides of the square. Find the area of the square.

Solution

Solution:

Call the point in question AA, the center of the circle OO, and its radius rr. Consider a right triangle BOABOA with hypotenuse OAOA: OAOA has length rr, and BOBO and BABA have lengths r1r-1 and r2r-2. By the Pythagorean theorem,
(r1)2+(r2)2=r2(r-1)^2 + (r-2)^2 = r^2
which gives
r26r+5=0r^2 - 6r + 5 = 0
so r=5r = 5 since r>4r > 4. The area of the square is (2r)2=100(2r)^2 = 100.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.