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Geometry Difficulty 4.8 AIME Prove it Singapore

A square is cut into several rectangles, none of which is a square, so that the sides of each rectangle are parallel to the sides of the square. For each rectangle with sides aa, bb, a<ba < b, compute the ratio a/ba/b. Prove that sum of these ratios is at least 11.

Solution

Without loss of generality, we may assume the square has area 11. Let the sides of the rectangles be aia_i, bib_i, aibia_i \leq b_i and Si=aibiS_i = a_i b_i. We have Si=1\sum S_i = 1 and
aibi=Sibi2Si=1. \sum \frac{a_i}{b_i} = \sum \frac{S_i}{b_i^2} \geq \sum S_i = 1.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.