Maths Olympiad Prep

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, 2020

Combinatorics Difficulty 4.0 AIME Find the answer United States

Problem:

The numbers 1,2,,101, 2, \ldots, 10 are written in a circle. There are four people, and each person randomly selects five consecutive integers (e.g. 1,2,3,4,51, 2, 3, 4, 5, or 8,9,10,1,28, 9, 10, 1, 2). If the probability that there exists some number that was not selected by any of the four people is pp, compute 10000p10000 p.

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

The unselected numbers must be consecutive. Suppose that {1,2,,k}\{1, 2, \ldots, k\} are the unselected numbers for some kk.

In this case, 11 cannot be selected, so there are 55 possible sets of consecutive numbers the people could have chosen. This leads to 545^{4} possibilities. Moreover, 1010 must be selected, so we must subtract 444^{4} possibilities where neither 11 nor 1010 are selected.

Therefore, accounting for the rotation of the unselected numbers, we find
p=10(5444)104=369010000. p = \frac{10\left(5^{4} - 4^{4}\right)}{10^{4}} = \frac{3690}{10000}.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.