The figure shows a semicircle, where B is a point on its diameter AC so that AB=6 and BC=12. The line perpendicular to this diameter meets the semicircle at D. The semicircles with diameters AB and BC, drawn as shown, meet AD and CD at E and F, respectively. Find the distance between E and F.
Solution
Solution:
Observe that DEFB is a rectangle so EF=DB. However, DB2=AB×BC=72. Thus, EF=62.
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Source: MathNet,
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