Let a, b, c, d be positive real numbers such that a2+b2+c2+d2=4. Prove that there are two of a, b, c, d with sum greater or equal to 2.
Solution
Without loss of generality, let a≥b≥c≥d and we will prove that a+b≥2. We have that ab≥c2 and ab≥d2, so by adding them we have: 2ab≥c2+d2. Therefore, (a+b)2=a2+b2+2ab≥a2+b2+c2+d2=4, so a+b≥2.
Want a route through all this instead of an archive? The track
puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.
Source: MathNet,
licensed CC-BY-4.0.
Statement and solution reproduced as published; topic and difficulty added by this site.