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Algebra Difficulty 3.8 AMC 10/12 Find the answer Slovenia

The first term of an arithmetic progression is equal to 13\frac{1}{3} and the third term is equal to 15\frac{1}{5}. What is the second term?

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Solution

The second term of the arithmetic progression is equal to a2=12(a1+a3)=12(13+15)=415a_2 = \frac{1}{2}(a_1 + a_3) = \frac{1}{2}\left(\frac{1}{3} + \frac{1}{5}\right) = \frac{4}{15}.

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