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Switzerland Selection Solution

Geometry Difficulty 4.4 AIME Prove it Switzerland

Problem:

Let ABCABC and AMNAMN be two similar, non-overlapping triangles with the same orientation, such that AB=ACAB = AC and AM=ANAM = AN. Let OO be the circumcentre of the triangle MABMAB. Prove that the points OO, CC, NN and AA lie on a circle if and only if the triangle ABCABC is equilateral.

Solution

Solution:

Figure 1

Let O′O' be the circumcentre of triangle NACNAC. Consider the rotation of center AA and angle ∠BAC\angle BAC: the conditions of the problem imply that it maps BB to CC and MM to NN. Moreover, because it fixes AA we know that it maps OO to O′O', and triangle AOO′AOO' is also similar to triangle ABCABC. Then

O,C,N,AO, C, N, A on a circle ⟺O′O=O′A⟺CB=CA⟺△ABC\Longleftrightarrow O'O = O'A \Longleftrightarrow CB = CA \Longleftrightarrow \triangle ABC equilateral, as desired.

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