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Combinatorics Difficulty 7.4 National Olympiad, round 2 Prove it Turkey

3m3m balls numbered 1,1,1,2,2,2,3,3,3,,m,m,m1, 1, 1, 2, 2, 2, 3, 3, 3, \dots, m, m, m are distributed into 88 boxes so that any two boxes contain identical balls. Find the minimal possible value of mm.

Solution

If some box contains a ball numbered ii then at most two other boxes can also contain ball numbered ii. Therefore, each box must contain at least 44 balls and consequently the total number of balls is at least 3232. Thus, m11m \ge 11. The example for m=11m = 11: (1,2,3,4)(1,2,3,4), (1,4,5,6)(1,4,5,6), (1,7,8,9)(1,7,8,9), (2,5,7,9)(2,5,7,9), (2,6,8,10)(2,6,8,10), (3,5,8,11)(3,5,8,11), (3,6,9,10,11)(3,6,9,10,11), (4,7,10,11)(4,7,10,11).

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.