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Harvard-MIT November Tournament

Geometry Difficulty 4.8 AIME Prove it United States

Problem:
Let AMOLAMOL be a quadrilateral with AM=10AM = 10, MO=11MO = 11, and OL=12OL = 12. Given that the perpendicular bisectors of sides AMAM and OLOL intersect at the midpoint of segment AOAO, find the length of side LALA.

Solution

Solution:
Let DD be the midpoint of AMAM and EE be the midpoint of AOAO. Then, we note that ADE∼AMOADE \sim AMO, so MM is a right angle. Similarly, LL is a right angle. Consequently, we get that
AO2=OM2+AM2⇒AL=AO2−OL2=112+102−122=77. AO^{2} = OM^{2} + AM^{2} \Rightarrow AL = \sqrt{AO^{2} - OL^{2}} = \sqrt{11^{2} + 10^{2} - 12^{2}} = \sqrt{77}.

Figure 1

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