Solution:
If two identical letters are adjacent or have a single letter in between, there is clearly a palindromic substring of length (respectively) two or three. So there cannot be any such substrings.
Say we have a permutation of the word REDDER without any palindromic substrings. Let us call the first letter X. The second letter has to be different, let us call it Y. The third letter cannot be X or Y, let it be Z. Again, the fourth letter cannot be Y or Z, and we only have 3 letters to choose from, so it has to be X. Continuing analogously, the fifth letter has to be Y, and the sixth letter has to be Z. So any word satisfying the problem statement has to be of the form XYZXYZ. It is easy to check that such a word indeed does not have any palindromic substrings. X,Y,Z can be any permutation of R, E, D, giving a total of 6 possibilities.