In the octagon COMPUTER exhibited below, all interior angles are either 90∘ or 270∘ and we have CO=OM=MP=PU=UT=TE=1.
Point D (not to scale in the diagram) is selected on segment RE so that polygons COMPUTED and CDR have the same area. Find DR.
Solution
Solution:
The area of the octagon COMPUTER is equal to 6. So, the area of CDR must be 3. So, we have the equation 21×CD×DR=[CDR]=3. And from CD=3, we have DR=2.
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Source: MathNet,
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