Problem:
Let be a finite set of positive real numbers. If 's average is at most but its product is at least , show that any three elements of can form the sides of a triangle.
Problem:
Let be a finite set of positive real numbers. If 's average is at most but its product is at least , show that any three elements of can form the sides of a triangle.
Solution:
Assume otherwise for the sake of contradiction, i.e. that there exist so that . For fixed , the product is then maximized when . Then, if have average , their product is at most that when , which happens at , , , for a product of .
Now consider replacing all of with in . The product multiplies by at least for a product of at least , while the average is unchanged, a contradiction to AM-GM.