AlgebraDifficulty 4.3AIMEFind the answerUnited States
Problem:
r and s are integers such that 3r≥2s−3 and 4s≥r+12. What is the smallest possible value of r/s?
A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.
Solution
Solution:
We simply plot the two inequalities in the sr-plane and find the lattice point satisfying both inequalities such that the slope from it to the origin is as low as possible. We find that this point is (2,4) (or (3,6)), as circled in the figure, so the answer is 2/4=1/2.
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Source: MathNet,
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