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Harvard-MIT Mathematics Tournament

Algebra Difficulty 4.3 AIME Find the answer United States

Problem:

rr and ss are integers such that
3r≥2s−3 and 4s≥r+12. 3 r \geq 2 s - 3 \text{ and } 4 s \geq r + 12.
What is the smallest possible value of r/sr / s?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:

We simply plot the two inequalities in the srs r-plane and find the lattice point satisfying both inequalities such that the slope from it to the origin is as low as possible. We find that this point is (2,4)(2,4) (or (3,6)(3,6)), as circled in the figure, so the answer is 2/4=1/22 / 4 = 1 / 2.

Figure 1

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.