Olympiad Maths Prep

Library / /7 of 11

Combinatorics Difficulty 5.9 AIME, harder Prove it Czech Republic

There are 100 diamonds on display; 50 of them genuine and 50 of them fake. Peter is the only person able to distinguish them. Whenever you point to three diamonds, Peter will cover one of them and (truthfully) tell you, how many of the remaining two are genuine. Determine if it is possible to find the 50 genuine diamonds, no matter how Peter answers your queries.
(Michal Rolínek, Josef Tkadlec)

Solution

We prove it is impossible. Let Peter pick one genuine diamond GG and one fake diamond FF. Whenever the triplet of diamonds being pointed to contains both FF and GG, Peter covers the third diamond (and truthfully answers “One.”). Whenever the triplet contains precisely one of FF, GG, Peter covers it. Otherwise he covers any diamond.
None of Peter's answers ever distinguishes between GG and FF hence it is impossible to say which of GG, FF is the genuine one and which is the fake one.

Looking for a route rather than an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement and solution reproduced as published; topic and difficulty added by this site.