Maths Olympiad Prep

Library / Baltic Way competition problems /1 of 45

Baltic Way competition problems

Algebra Difficulty 4.3 AIME Prove it Baltic Way

Let xx be a positive acute angle. Prove that
cos⁡2(x)cot⁡(x)+sin⁡2(x)tan⁡(x)≥1 \cos^2(x) \cot(x) + \sin^2(x) \tan(x) \ge 1

Solution

The geometric-arithmetic inequality gives
cos⁡xsin⁡x≤cos⁡2x+sin⁡2x2=12. \cos x \sin x \le \frac{\cos^2 x + \sin^2 x}{2} = \frac{1}{2}.
It follows that
1=(cos⁡2x+sin⁡2x)2=cos⁡4x+sin⁡4x+2cos⁡2xsin⁡2x≤cos⁡4x+sin⁡4x+12 1 = (\cos^2 x + \sin^2 x)^2 = \cos^4 x + \sin^4 x + 2 \cos^2 x \sin^2 x \le \cos^4 x + \sin^4 x + \frac{1}{2}
so
cos⁡4x+sin⁡4x≥12≥cos⁡xsin⁡x. \cos^4 x + \sin^4 x \ge \frac{1}{2} \ge \cos x \sin x.
The required inequality follows.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.