Let $r$ be the radius of the ball and $O$ be its first position on the plane. First, we roll the ball (sphere) on its great circle that passes through the marked point and the top point of the ball, until the mark be on top of the ball. Let $A$ be the current position of the ball on the plane. It is trivial that $OA < 2\pi r$. So there exists a point $B$ on the plane so that $AB = OB = 2\pi r$. Now we roll the ball from $A$ to $B$ on the segment $AB$, and since $AB = 2\pi r$, the mark will be at the top of the ball. Then we roll the ball from $B$ to $O$ on $BO$ and the mark is at the top of the ball while it is on its first position.