Solution:
Put x−y=r, y−z=s. Then z−x=−(r+s), and
(x−y)5+(y−z)5+(z−x)5=r5+s5−(r+s)5
Expand (r+s)5:
(r+s)5=r5+5r4s+10r3s2+10r2s3+5rs4+s5
So,
r5+s5−(r+s)5=r5+s5−[r5+5r4s+10r3s2+10r2s3+5rs4+s5]
=−5r4s−10r3s2−10r2s3−5rs4
=−5rs(r3+2r2s+2rs2+s3)
=−5rs(r2+rs+s2)(r+s)
Therefore,
(x−y)5+(y−z)5+(z−x)5=−5rs(r+s)(r2+rs+s2)
Recall r=x−y, s=y−z, r+s=x−y+y−z=x−z=−(z−x).
Thus, rs(r+s)=(x−y)(y−z)(z−x) (up to sign), and the expression is divisible by 5(x−y)(y−z)(z−x).