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All-Soviet-Union Mathematical Olympiad

Combinatorics Difficulty 4.9 AIME Prove it Soviet Union

Problem:
How many (algebraically) different expressions can we obtain by placing parentheses in a1/a2/…/ana_1 / a_2 / \ldots / a_n?

Solution

Solution:
Answer 2n−22^{n - 2}. a1a_1 must be in the numerator, and a2a_2 must be in the denominator, but the other symbols can be in either. This is easily proved by induction.

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