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Algebra Difficulty 4.8 AIME Prove it Saudi Arabia

Find all integers nn such that there exists a polynomial P(x)P(x) with integer coefficients satisfying
P(n23+n3)=2016n+20n23+16n3. P\left(\sqrt[3]{n^{2}}+\sqrt[3]{n}\right)=2016 n+20 \sqrt[3]{n^{2}}+16 \sqrt[3]{n} .

Solution

First, we prove 2 lemmas as the problem in Level 4's Test. Then turn to the problem, since P(n23+n3)=2016n+20n23+16n3P\left(\sqrt[3]{n^{2}}+\sqrt[3]{n}\right)=2016 n+20 \sqrt[3]{n^{2}}+16 \sqrt[3]{n}, then by the second lemma, we obtain n12016=4n-1 \mid 20-16=4.
That is, n{5,3,2,0,1,3}n \in\{5,3,2,0,-1,-3\}, and we can easily check that these numbers satisfy the condition of the problem. \square

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