Maths Olympiad Prep

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Geometry Difficulty 4.4 AIME Prove it United States

Problem:

Let ABCDABCD be an isosceles trapezoid, and let EE be the foot of the altitude from AA to line BCBC. Prove that line DEDE passes through the centroid of ABC\triangle ABC.

Solution

Solution:

Let MM be the midpoint of BCBC. Also, let FF be the foot from DD to BCBC. Then AEFDAEFD is a rectangle. Define GG as the intersection of AMAM and DEDE. Then AGDEMG\triangle AGD \sim \triangle EMG, and we get

GMGA=MEDA=MEFE=12 \frac{GM}{GA} = \frac{ME}{DA} = \frac{ME}{FE} = \frac{1}{2}

which implies GG is the centroid of ABC\triangle ABC, since the centroid divides the AA-median in a 2:12:1 ratio. Thus GG lies on DEDE.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.