Maths Olympiad Prep

Library / /917 of 1394

, 2019

Geometry Difficulty 5.4 AIME, harder Prove it United States

Problem:

Tessa has a figure created by adding a semicircle of radius 11 on each side of an equilateral triangle with side length 22, with semicircles oriented outwards. She then marks two points on the boundary of the figure. What is the greatest possible distance between the two points?

Solution

Solution:

Note that both points must be in different semicircles to reach the maximum distance. Let these points be MM and NN, and O1O_{1} and O2O_{2} be the centers of the two semicircles where they lie respectively. Then
MNMO1+O1O2+O2N MN \leq MO_{1} + O_{1}O_{2} + O_{2}N
Note that the right side will always be equal to 33 (MO1=O2N=1MO_{1} = O_{2}N = 1 from the radius condition, and O1O2=1O_{1}O_{2} = 1 from being a midline of the equilateral triangle), hence MNMN can be at most 33. Finally, if the four points are collinear (when MM and NN are defined as the intersection of line O1O2O_{1}O_{2} with the two semicircles), then equality will hold. Therefore, the greatest possible distance between MM and NN is 33.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.