Maths Olympiad Prep

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Geometry Difficulty 4.7 AIME Prove it Soviet Union

Problem:
Let f(x)=acos(x+1)+bcos(x+2)+ccos(x+3)f(x) = a\cos(x + 1) + b\cos(x + 2) + c\cos(x + 3), where aa, bb, cc are real. Given that f(x)f(x) has at least two zeros in the interval (0,π)(0,\pi), find all its real zeros.

Solution

Solution:
Answer: f(x)f(x) must be identically zero.

We have f(x)=(acos1+bcos2+ccos3)cosx(asin1+bsin2+csin3)sinxf(x) = (a\cos 1 + b\cos 2 + c\cos 3)\cos x - (a\sin 1 + b\sin 2 + c\sin 3)\sin x. This can be written as dcos(x+θ)d\cos(x + \theta) for some dd, θ\theta. But if d0d \neq 0, then this has only one zero in the interval (0,π)(0,\pi). Hence d=0d = 0.

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