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Geometry Difficulty 4.3 AIME Find the answer China

Assume that M={(x,y)x2+2y2=3}M = \{(x, y) \mid x^2 + 2y^2 = 3\}, and N={(x,y)y=mx+b}N = \{(x, y) \mid y = mx + b\}. If MNM \cap N \neq \emptyset for all mRm \in \mathbb{R}, then bb takes values from:

Pick one

Solution

For any mRm \in \mathbb{R} we have MNM \cap N \neq \emptyset, which means point (0,b)(0, b) is on or in the ellipsoid x23+2y23=1\frac{x^2}{3} + \frac{2y^2}{3} = 1. Therefore
2b231, or 62b62. \frac{2b^2}{3} \le 1, \text{ or } -\frac{\sqrt{6}}{2} \le b \le \frac{\sqrt{6}}{2}.
Answer: A.

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