Competition problem — Algebra — Maths Olympiad Prep

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Algebra Difficulty 3.8 AMC 10/12 Find the answer South Africa

If $\frac{20}{3} = \frac{120}{y}$ then $y$ equals

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Solution

If the numerator has been multiplied by $6$ and the fraction stays the same, the denominator is also multiplied by $6$ and becomes $3 \times 6 = 18$ .

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