Maths Olympiad Prep

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Geometry Difficulty 5.4 AIME, harder Prove it China

ABAB is a diameter of the circle OO, the point CC lies on the extended line ABAB produced. A line passing through CC intersects with the circle OO at points DD and EE. OFOF is a diameter of the circumcircle O1O_1 of BOD\triangle BOD. Join CFCF and its extension, which intersects the circle O1O_1 at GG. Prove that points OO, AA, EE, GG are concyclic.

Solution

Figure 1

Thus, GG, AA, CC, DD are concyclic. Hence,
AGC=ADC, \angle AGC = \angle ADC, \qquad ①
AGC=AGO+OGF=AGO+π2, \angle AGC = \angle AGO + \angle OGF = \angle AGO + \frac{\pi}{2}, \qquad ②
ADC=ADB+BDC=BDC+π2. \angle ADC = \angle ADB + \angle BDC = \angle BDC + \frac{\pi}{2}. \qquad ③
Combining ①, ② and ③ yields
AGO=BDC. \angle AGO = \angle BDC. \qquad ④
Since BB, DD, EE, AA are concyclic, we have
BDC=EAO. \angle BDC = \angle EAO. \qquad ⑤
As OA=OEOA = OE, we obtain
EAO=AEO. \angle EAO = \angle AEO. \qquad ⑥
Combining ④, ⑤ and ⑥ implies AGO=AEO\angle AGO = \angle AEO.
Therefore, OO, AA, EE, GG are concyclic.

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