Olympiad Maths Prep

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Geometry Difficulty 5.5 AIME, harder Prove it Belarus

Let ABCABC be a triangle with AB=ACAB = AC, and let MM be the midpoint of BCBC. Let PP be a point such that PB<PCPB < PC and PAPA is parallel to BCBC. Let XX and YY be points on the lines PBPB and PCPC, respectively, so that BB lies on the segment PXPX, CC lies on the segment PYPY and PXM=PYM\angle PXM = \angle PYM.
Prove that the quadrilateral APXYAPXY is cyclic.

Solution

1. See IMO 2018 Shortlist, Problem G2.

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