Maths Olympiad Prep

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Geometry Difficulty 5.2 AIME, harder Prove it Soviet Union

Problem:

An octagon has equal angles. The lengths of the sides are all integers. Prove that the opposite sides are equal in pairs.

Solution

Solution:

Extend the sides to form two rectangles. Let the sides of the octagon have length aa, bb, cc, dd, ee, ff, gg, hh. Then we can find the rectangle sides. For example, one of the rectangles has opposite sides a+b+h2a + \frac{b + h}{\sqrt{2}} and e+d+f2e + \frac{d + f}{\sqrt{2}}. Hence either a=ea = e or 2=b+hdfae\sqrt{2} = \frac{b + h - d - f}{a - e}. The root is irrational, so we must have a=ea = e. Similarly for the other pairs of opposite sides.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.