Maths Olympiad Prep

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Algebra Difficulty 3.9 AMC 10/12 Find the answer Italy

Problem:

Given two positive real numbers a,ba, b we define
ab=ab+1a+b a \star b=\frac{a b+1}{a+b}
What is the value of 1(2(3((20172018))))1 \star(2 \star(3 \star(\cdots(2017 \star 2018))))?

Pick one

Solution

Solution:

The answer is (B)\mathbf{( B )}. One can observe that for any positive real number xx we have 1x=1x+11+x=11 \star x= \frac{1 \cdot x+1}{1+x}=1; taking as xx the value 2(3((20172018)))2 \star(3 \star(\cdots(2017 \star 2018))) one obtains that the answer to the problem is 1x=11 \star x=1.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from it; metadata (topic, difficulty) added by this project.