Maths Olympiad Prep

Library / /3 of 68

Algebra Difficulty 4.5 AIME Prove it Estonia

Find the largest remainder that can be left over when dividing the number 20192019 by a three-digit natural number.

Solution

If 673<m<1000673 < m < 1000 then dividing 20192019 by mm gives quotient 22 and remainder 20192m2019 - 2m. Obviously the remainder increases when mm decreases. Thus in the case m=674m = 674 we obtain the largest remainder 671671.

Dividing 20192019 by 673673 gives remainder 00. Dividing 20192019 by 672672 or any smaller number gives remainder that does not exceed 671671. Consequently, the largest remainder under the given conditions is 671671.

Want a route through all this instead of an archive? The track puts 2,000 problems in a working order, from AMC 10 level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.