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Algebra Difficulty 4.6 AIME Prove it Romania
Given x1,x2,…,xn real numbers, prove that there exists a real number y such that
{y−x1}+{y−x2}+⋯+{y−xn}≤2n−1.
Solution
As {a}+{−a}≤1,∀a∈R (with equality if a is not an integer), we have
1≤i=j≤n∑{xi−xj}≤2n(n−1),
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Source: MathNet,
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