Consider the tile placement obtained by superposing the two given arrangements below. In this placement, each square of the board should be covered by at most two tiles. Furthermore, with the exception of the central square, each of the 24 remaining squares are covered by at least one tile.


Next, we will prove that the number of squares covered by at least one tile is no more than 24. Let us annotate some squares with the letters A and B as shown in the figure below. Then, no matter how a single tile is placed, exactly one square marked with A and exactly one square marked with B will be covered by the tile. Note that there are 4 squares marked with A. Since each square is covered by at most two tiles, the total number of tiles that can be placed is at most 8. Therefore, it is impossible to cover all of the 9 squares marked with B. Hence, the number of squares covered by at least one tile is 25−1=24 or less.

With the above argument, we have proved that the maximum value in question is 24.