Maths Olympiad Prep

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HMMT February

Combinatorics Difficulty 5.2 AIME, harder Prove it United States

Problem:
A contest has six problems worth seven points each. On any given problem, a contestant can score either 00, 11, or 77 points. How many possible total scores can a contestant achieve over all six problems?

Solution

Solution:
For 0≤k≤60 \leq k \leq 6, to obtain a score that is k(mod6)k \pmod{6}, exactly kk problems must get a score of 11. The remaining 6−k6-k problems can generate any multiple of 77 from 00 to 7(6−k)7(6-k), of which there are 7−k7-k. So the total number of possible scores is ∑k=06(7−k)=28\sum_{k=0}^{6}(7-k)=28.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.