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Geometry Difficulty 4.5 AIME Prove it Austria

Let ABCABC be an acute triangle and DD be a point on the altitude through CC.
Prove that the mid-points of the line segments ADAD, BDBD, BCBC and ACAC form a rectangle.

Solution

We denote with MXYM_{XY} the mid-point of the line segment XYXY.
Using the intercept theorem, we deduce that
* MADMBDM_{AD}M_{BD} is parallel to ABAB.
* MACMBCM_{AC}M_{BC} is parallel to ABAB.
* MACMADM_{AC}M_{AD} is parallel to CDCD.
* MBCMBDM_{BC}M_{BD} is parallel to CDCD.
Therefore, MADMBDM_{AD}M_{BD} is parallel to MACMBCM_{AC}M_{BC} and MACMADM_{AC}M_{AD} is parallel to MBCMBDM_{BC}M_{BD}.
Furthermore, MACMBCM_{AC}M_{BC} is orthogonal to MACMADM_{AC}M_{AD}, since CDCD is orthogonal to ABAB.
Therefore, the four mid-points form a rectangle. \square

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