Maths Olympiad Prep

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Geometry Difficulty 4.7 AIME Find the answer United States

Problem:
A tree grows in a rather peculiar manner. Lateral cross-sections of the trunk, leaves, branches, twigs, and so forth are circles. The trunk is 11 meter in diameter to a height of 11 meter, at which point it splits into two sections, each with diameter 0.50.5 meter. These sections are each one meter long, at which point they each split into two sections, each with diameter 0.250.25 meter. This continues indefinitely: every section of tree is 11 meter long and splits into two smaller sections, each with half the diameter of the previous.
What is the total volume of the tree?

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

Solution:
If we count the trunk as level 00, the two sections emerging from it as level 11, and so forth, then the nnth level consists of 2n2^{n} sections each with diameter 1/2n1 / 2^{n}, for a volume of 2n(π/422n)=(π/4)2n2^{n}\left(\pi / 4 \cdot 2^{-2 n}\right) = (\pi / 4) \cdot 2^{-n}. So the total volume is given by a simple infinite sum,
0.25π(1+1/2+1/4+)=0.25π2=π/2. 0.25 \pi \cdot (1 + 1/2 + 1/4 + \ldots) = 0.25 \pi \cdot 2 = \pi / 2.

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.