GeometryDifficulty 5.0AIME, harderProve itUnited States
Problem:
There are circles ω1 and ω2. They intersect in two points, one of which is the point A. B lies on ω1 such that AB is tangent to ω2. The tangent to ω1 at B intersects ω2 at C and D, where D is the closer to B. AD intersects ω1 again at E. If BD=3 and CD=13, find EB/ED.
Solution
Solution:
> [diagram]
By power of a point, BA=BD⋅BC=43. Also, DEB∼DBA, so EB/ED=BA/BD=43/3.
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Source: MathNet,
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