Maths Olympiad Prep

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, 2010

Algebra Difficulty 4.9 AIME Prove it Estonia

Let aa be a fixed real number. Find all real numbers bb such that, for every real number xx, at least one of the numbers x2+ax+bx^2 + ax + b and x2ax+bx^2 - ax + b is non-negative.

Solution

Note that x2+ax+bx^2 + ax + b and x2ax+bx^2 - ax + b sum up to 2x2+2b2x^2 + 2b. If b0b \ge 0, then it is non-negative for arbitrary real number xx, implying that at least one of the numbers added was non-negative. If b<0b < 0, then taking x=0x = 0 turns both summands negative.

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