Maths Olympiad Prep

Library / Belarusian Mathematical Olympiad /27 of 208

Belarusian Mathematical Olympiad

Algebra Difficulty 5.2 AIME, harder Prove it Belarus

Does there exist a function f(x):R→Rf(x): \mathbb{R} \to \mathbb{R} satisfying the equality
f(∣x∣)+∣f(x)∣=x f(|x|) + |f(x)| = x
for all real numbers xx?

Solution

Answer: no, such function doesn't exist.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.