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PMO National Stage Oral Phase

Geometry Difficulty 4.4 AIME Prove it Philippines

Problem:

Let □ABCD\square ABCD be a trapezoid with parallel sides ABAB and CDCD of lengths 6 units and 8 units, respectively. Let EE be the point of intersection of the extensions of the nonparallel sides of the trapezoid. If the area of △BEA\triangle BEA is 60 square units, what is the area of △BAD\triangle BAD?

Solution

Solution:

Note that △BEA∼△CED\triangle BEA \sim \triangle CED and ∣EB∣=2⋅606=20|EB| = \frac{2 \cdot 60}{6} = 20. Thus, ∣EC∣=86⋅20=803|EC| = \frac{8}{6} \cdot 20 = \frac{80}{3}, and hence ∣BC∣=803−20=203|BC| = \frac{80}{3} - 20 = \frac{20}{3}. Finally then,
area of △BAD=12⋅6⋅203=20 \text{area of } \triangle BAD = \frac{1}{2} \cdot 6 \cdot \frac{20}{3} = 20

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Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.