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Belarusian Mathematical Olympiad

Number theory Difficulty 5.5 AIME, harder Prove it Belarus

Find all possible values of digits aa and bb such that
(ab)3=(a−3)(b−3)(b+2)(a+2)ab‾. (ab)^3 = \overline{(a-3)(b-3)(b+2)(a+2)ab}.
(As usual, by xyz‾\overline{xyz} we denote an integer number, which decimal representation consists of digits x,y,…,zx, y, \dots, z in that order.)

Solution

a=7,b=6a = 7, b = 6.

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