GeometryDifficulty 5.3AIME, harderProve itUnited States
Problem:
Let T be a trapezoid with two right angles and side lengths 4,4,5, and 17. Two line segments are drawn, connecting the midpoints of opposite sides of T and dividing T into 4 regions. If the difference between the areas of the largest and smallest of these regions is d, compute 240d.
Solution
Solution:
By checking all the possibilities, one can show that T has height 4 and base lengths 4 and 5. Orient T so that the shorter base is on the top.
Then, the length of the cut parallel to the bases is 24+5=29. Thus, the top two pieces are trapezoids with height 2 and base lengths 2 and 49, while the bottom two pieces are trapezoids with height 2 and base lengths 49 and 25. Thus, using the area formula for a trapezoid, the difference between the largest and smallest areas is
d=2(25+49−49−2)⋅2=21
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Source: MathNet,
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