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Belarusian Mathematical Olympiad

Algebra Difficulty 4.9 AIME Prove it Belarus

Find all functions f(x):R→Rf(x): \mathbb{R} \to \mathbb{R} satisfying the equality
x=−12f(∣x∣)+∣f(x)∣ x = -\frac{1}{2}f(|x|) + |f(x)|
for all real numbers xx.

Solution

f(x)=2xf(x) = 2x for all x≥0x \ge 0 and f(x)=0f(x) = 0 for all x<0x < 0.

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