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Geometry Difficulty 4.9 AIME Prove it Romania

A triangle ABCABC has its orthocenter HH distinct from its vertices and from the circumcenter OO. Denote M,N,PM, N, P the circumcenters of the triangles HBC,HCAHBC, HCA, respectively HABHAB. Prove that the lines AM,BN,CPAM, BN, CP and OHOH are concurrent.
Petru Braica

Solution

If DD is the midpoint of [BC][BC], then OD=12(OB+OC)=12(OHOA)=12AH\overrightarrow{OD} = \frac{1}{2}(\overrightarrow{OB} + \overrightarrow{OC}) = \frac{1}{2}(\overrightarrow{OH} - \overrightarrow{OA}) = \frac{1}{2}\overrightarrow{AH}, hence OM=AH\overrightarrow{OM} = \overrightarrow{AH}.
It follows that AHMOAHMO is a parallelogram, hence AMAM passes through the midpoint of the segment [OH][OH], the same being true for BNBN and CPCP.

Figure 1

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