Maths Olympiad Prep

Library / Bulgarian Mathematical Competitions /33 of 92

Bulgarian Mathematical Competitions

Combinatorics Difficulty 5.6 AIME, harder Prove it Bulgaria

Problem:

Aleksander writes a positive integer as a coefficient of a polynomial of degree four, then Elitza writes a positive integer as another coefficient of the same polynomial and so on till all the five coefficients of the polynomial are filled in. Aleksander wins if the polynomial obtained has an integer root; otherwise, Elitza wins. Who of them has a winning strategy?

Solution

Solution:

We shall prove that Elitza has a winning strategy. If the polynomial is a0x4+a1x3+a2x2+a3x+a4a_{0} x^{4} + a_{1} x^{3} + a_{2} x^{2} + a_{3} x + a_{4} and Aleksander writes a0a_{0}, a1a_{1}, a2a_{2} or a3a_{3}, then Elitza writes respectively a1=a0a_{1} = a_{0}, a0=a1a_{0} = a_{1}, a3=a2a_{3} = a_{2} or a2=a3a_{2} = a_{3}; if he writes a4a_{4}, she writes a1=1a_{1} = 1.

In a similar way Elitza is able to get a1≤a0a_{1} \leq a_{0} and a3≤a2a_{3} \leq a_{2} after her second move. Suppose that the polynomial obtained has an integer root −y-y. Then y≥1y \geq 1 and hence a4=y3(a1−a0y)+a3−a2y≤0a_{4} = y^{3}(a_{1} - a_{0} y) + a_{3} - a_{2} y \leq 0, which is a contradiction.

Want a route through all this instead of an archive? The track puts 2,604 problems in a working order, from Junior Challenge level to the IMO shortlist.

Source: MathNet, licensed CC-BY-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.